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ICL8038
0.22 × V SUPPLY
C × V C × 1/3V SUPPLY
A B
t2
0.66 ( 2R A – R )
2 ( 0.22 ) ------------------------ – 0.22 ------------------------
A
B
f = ---------------- = ------------------------------------------------------
0.66 ?
2R A – R B ?
f = ----------- (for Figure 3A)
The levels of the current sources can, however, be selected
over a wide range with two external resistors. Therefore, with
the two currents set at values different from I and 2I, an
asymmetrical sawtooth appears at Terminal 3 and pulses
with a duty cycle from less than 1% to greater than 99% are
available at Terminal 9.
The sine wave is created by feeding the triangle wave into a
nonlinear network (sine converter). This network provides a
decreasing shunt impedance as the potential of the triangle
moves toward the two extremes.
Waveform Timing
The symmetry of all waveforms can be adjusted with the
external timing resistors. Two possible ways to accomplish
this are shown in Figure 3. Best results are obtained by
keeping the timing resistors R A and R B separate (A). R A
controls the rising portion of the triangle and sine wave and
the 1 state of the square wave.
The magnitude of the triangle waveform is set at 1 / 3
V SUPPLY ; therefore the rising portion of the triangle is,
FIGURE 2A. SQUARE WAVE DUTY CYCLE - 50%
0.66 I
C × V C × 1/3 × V SUPPLY × R A R A × C
t 1 = -------------- = ------------------------------------------------------------------- = ------------------
The falling portion of the triangle and sine wave and the 0
state of the square wave is:
R R C
= ------------- = ----------------------------------------------------------------------------------- = -------------------------------------
1 V V
SUPPLY SUPPLY B
R R
Thus a 50% duty cycle is achieved when R A = R B .
If the duty cycle is to be varied over a small range about 50%
only, the connection shown in Figure 3B is slightly more
convenient. A 1k Ω potentiometer may not allow the duty cycle
to be adjusted through 50% on all devices. If a 50% duty cycle
is required, a 2k Ω or 5k Ω potentiometer should be used.
With two separate timing resistors, the frequency is given by:
1 1
t 1 + t 2 R A C ? R B ?
------------ ? 1 + ------------------------- ?
or, if R A = R B = R
0.33
RC
FIGURE 2B. SQUARE WAVE DUTY CYCLE - 80%
FIGURE 2. PHASE RELATIONSHIP OF WAVEFORMS
V+
R A
R B
R L
V+
R A
1k Ω
R B
R L
7
4
5
6
9
7
4
5
6
9
8
10
C
ICL8038
11
3
12 2
82K
8
10
C
ICL8038
11
3
12 2
100K
FIGURE 3A.
V- OR GND
FIGURE 3B.
V- OR GND
FIGURE 3. POSSIBLE CONNECTIONS FOR THE EXTERNAL TIMING RESISTORS
5
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